36+b^2=400

Solution for 36+b^2=400 equation:

36+b^2=400

We move all terms to the left:

36+b^2-(400)=0

We add all the numbers together, and all the variables

b^2-364=0

a = 1; b = 0; c = -364;
Δ = b2-4ac
Δ = 02-4·1·(-364)
Δ = 1456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1456}=\sqrt{16*91}=\sqrt{16}*\sqrt{91}=4\sqrt{91}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{91}}{2*1}=\frac{0-4\sqrt{91}}{2}
=-\frac{4\sqrt{91}}{2}
=-2\sqrt{91}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{91}}{2*1}=\frac{0+4\sqrt{91}}{2}
=\frac{4\sqrt{91}}{2}
=2\sqrt{91}
$